d: \(\dfrac{1}{8}x^3-27=\left(\dfrac{1}{2}x-3\right)\left(\dfrac{1}{4}x^2+\dfrac{3}{2}x+9\right)\)
e: \(\left(3-2q\right)^2=4q^2-12q+9\)
`c, (2-xy)^3`
`= 8-12xy+6x^2y^2-x^3y^3`
`d, 1/8x^3-27`
`=(1/2x-3)(1/4x^2+3/2x+9)`
`e, (3-2q)^2`
`=4q^2-12q^2+9`
f, Xem lại đề