Question

Answer 1

\(a,=\left(2022-2\right)^2\\ =\left(2020\right)^2=4080400\\ b,=-\left(x^3-6x^2+12x-8\right)\\ =-\left(x-2\right)^3\\ =-\left(-2-2\right)^3\\ =-\left(-4\right)^3\\ =-\left(-64\right)=64\)

Answer 2

`a)2022^2-2.4044+4=2022^2-2.2022.2+2^2=(2022-2)^2=2020^2=4080400`

`b)8-12x+6x^2-x^3=2^3-3.2^2 .x+3.2.x^2-x^3=(2-x)^3`

Thay `x=-2` vào bth có: `[2-(-2)]^3=64`