=>-2/3x=1/4-1/5=1/20
=>x=-1/20:2/3=-1/20x3/2=-3/40
`-(2)/(3).x+0,2=(-(1)/(2))^{2}`
`=>-(2)/(3)x+(2)/(10)=(1)/(4)`
`=>-(2)/(3)x=(1)/(4)-(2)/(10)=(5)/(20)-(4)/(20)`
`=>-(2)/(3)x=1/20`
`=>x=(1)/(20):(-(2)/(3))=(1)/(20).(-(3)/(2))`
`=>x=-3/40`
\(\dfrac{-2}{3}.x+0,2=\left(\dfrac{-1}{2}\right)^2\)
=>\(\dfrac{-2}{3}.x+0,2=\dfrac{1}{4}\)
=>\(\dfrac{-2}{3}.x=\dfrac{1}{4}-0,2\)
=>\(\dfrac{-2}{3}.x=\dfrac{1}{20}\)
=>\(x=\dfrac{1}{20}:\dfrac{-2}{3}\)
=>x=\(\dfrac{-3}{40}\)
Vậy x=-3/40