a: \(\Leftrightarrow6x\left(x-3\right)\left(x-2\right)=0\)
hay \(x\in\left\{0;2;3\right\}\)
b: =>(x-7)2=0
=>x-7=0
=>x=7
\(a,6x^{^2}\left(x-3\right)-12x\left(x-3\right)=0\\ \Leftrightarrow6x\left(x-3\right)\left(x-2\right)=0\)
=>6x=0=>x=0
hoặc x=3
hoặc x=2
\(b,\Leftrightarrow\left(x-7\right)^{^2}=0\Leftrightarrow x=7\)
\(c,\Leftrightarrow\left(x-7-3x\right)\left(x-7+3x\right)=0\\ \Leftrightarrow\left(-2x-7\right)\left(4x-7\right)=0\)
\(\Rightarrow x=\dfrac{-7}{2}\)hoặc\(x=\dfrac{7}{4}\)
a. 6x2(x-3)-12x(x-3)=0
(x-3)(6x2-12x)=0
=> x-3=0 hoặc 6x2-12x=0
=>x=3 hoặc 6x(x-2)=0
=> x=3 hoặc x=0 hoặc x=2
Vậy x=....
b. =>(x-7)2=0
x-7=0
x=7
c. (x-7)2 -(3x)2=0
(x-7-3x)(x-7+3x)=0|
=> -2x=7 hoặc 4x=7
=> x=-7/2 hoặc 7/4
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