Xét hình thang `DEPF` có :
\(\widehat{D}+\widehat{E}+\widehat{P}+\widehat{F}=360^0\)
Mà : \(\widehat{D}=125^0\)
\(\widehat{E}=110^0\)
\(\widehat{P}=55^0\)
`=>` \(\widehat{F}=360^0-\widehat{D}-\widehat{E}-\widehat{P}\)
`=>` \(\widehat{F}=70^0\)
Vậy \(\widehat{F}=70^0\)