a: 3x-2=10
=>3x=12
hay x=4
b: \(\dfrac{3x+2}{x-1}=1+\dfrac{x}{x-1}\)
=>3x+2=x-1+x
=>3x+2=2x-1
=>x=-3
c: 3x(x-1)-2(1-x)=0
=>3x(x-1)+2(x-1)=0
=>(x-1)(3x+2)=0
=>x=1 hoặc x=-2/3
a.
\(3x-2=10\)
\(\Leftrightarrow3x=12\)
\(\Leftrightarrow x=4\)
b.
ĐKXĐ: \(x\ne1\)
\(\dfrac{3x+2}{x-1}=\dfrac{x-1}{x-1}+\dfrac{x}{x-1}\)
\(\Rightarrow3x+2=x-1+x\)
\(\Leftrightarrow3x+2=2x-1\)
\(\Leftrightarrow x=-3\) (thỏa mãn)
c.
\(3x\left(x-1\right)-2\left(1-x\right)=0\)
\(\Leftrightarrow3x\left(x-1\right)+2\left(x-1\right)=0\)
\(\Leftrightarrow\left(3x+2\right)\left(x-1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}3x+2=0\\x-1=0\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=-\dfrac{2}{3}\\x=1\end{matrix}\right.\)
