a: \(A=\dfrac{x^2-1+4x-4-x^2+2x-1}{\left(x-1\right)\left(x+1\right)}\cdot\dfrac{x\left(x+1\right)}{\left(x-2\right)^2}\)
\(=\dfrac{6\left(x-1\right)}{\left(x-1\right)}\cdot\dfrac{x}{\left(x-2\right)^2}=\dfrac{6}{\left(x-2\right)^2}\)
b: Thay x=1/2 vào A, ta được:
\(A=6:\left(\dfrac{1}{2}-2\right)^2=6:\left(-\dfrac{3}{2}\right)^2=6:\dfrac{9}{4}=6\cdot\dfrac{4}{9}=\dfrac{8}{3}\)