a: \(\Leftrightarrow x\cdot\dfrac{1}{12}=\dfrac{1}{12}+\dfrac{10}{12}=\dfrac{11}{12}\)
hay x=11
b: \(\Leftrightarrow x\cdot\dfrac{19}{15}=\dfrac{2}{3}+\dfrac{3}{5}=\dfrac{19}{15}\)
hay x=1
\(a.\dfrac{x}{12}-\dfrac{5}{6}=\dfrac{1}{12}\\ \dfrac{x}{12}=\dfrac{1}{12}+\dfrac{5}{6}\\ \dfrac{x}{12}=\dfrac{11}{12}\\ x=11\\ b.\dfrac{2}{3}-1\dfrac{4}{15}x=\dfrac{-3}{5}\\ \dfrac{19}{15}x=\dfrac{2}{3}+\dfrac{3}{5}\\ \dfrac{19}{15}x=\dfrac{19}{15}\\ x=1\)
\(a,\Rightarrow\dfrac{x}{12}=\dfrac{1}{12}+\dfrac{5}{6}=\dfrac{11}{12}\Rightarrow x=11\\ b,\Rightarrow\dfrac{19}{15}x=\dfrac{2}{3}+\dfrac{3}{5}=\dfrac{19}{15}\\ \Rightarrow x=1\)
