Question

Answer 1

a) \(=7\left(x^2-3x+2\right)=7\left[x\left(x-1\right)-2\left(x-1\right)\right]=7\left(x-1\right)\left(x-2\right)\)

b) \(=2\left(x^2-4x+3\right)=2\left[x\left(x-3\right)-\left(x-3\right)\right]=2\left(x-3\right)\left(x-1\right)\)

c) \(=x\left(x-4\right)-\left(x-4\right)=\left(x-4\right)\left(x-1\right)\)

Answer 2

\(a,=7\left(x^2-3x+2\right)=7\left(x^2-2x-x+2\right)=7\left(x-2\right)\left(x-1\right)\\ b,=2x^2-2x-6x+6=\left(2x-6\right)\left(x-1\right)=2\left(x-3\right)\left(x-1\right)\\ c,=x^2-4x-x+4=\left(x-4\right)\left(x-1\right)\)