\(a,VP=\dfrac{\left(2-x\right)\left(x^2+2x+4\right)}{x\left(x^2+2x+4\right)}=\dfrac{-\left(x-2\right)}{x}=\dfrac{x-2}{-x}=VT\\ b,VP=\dfrac{3x\left(y-x\right)}{\left(y-x\right)\left(y+x\right)}=\dfrac{3x}{y+x}=VT\\ c,VT=\dfrac{\left(x+y\right)\cdot3a\left(x+y\right)}{3a\cdot3a\left(x+y\right)}=\dfrac{3a\left(x+y\right)^2}{9a^2\left(x+y\right)}=VP\)