Question

Answer 1

\(a,=x^2\left(x+3\right)\\ b,=\left(x^2-4\right)\left(x-1\right)=\left(x-2\right)\left(x+2\right)\left(x-1\right)\\ c,=x\left(x^2-2x+1-y^2\right)=x\left[\left(x-1\right)^2-y^2\right]=x\left(x-y-1\right)\left(x+y-1\right)\\ d,=x^2-2x-3x+6=\left(x-2\right)\left(x-3\right)\\ e,Sửa:x^3-x+3x^2y-y+3xy^2+y^3\\ =\left(x+y\right)^3-\left(x+y\right)=\left[\left(x+y\right)^2-1\right]\left(x+y\right)\\ =\left(x+y-1\right)\left(x+y+1\right)\left(x+y\right)\)

Answer 2

a: \(=x^2\left(x+3\right)\)

d: \(=\left(x-2\right)\left(x-3\right)\)