\(x^3-5x^2+x=5\)
\(\Leftrightarrow x-5=0\)
hay x=5
Vậy: Chọn B
`x^3-5x^2+x=5`
`<=>x(x^2+1)=5(x^2+1)`
`<=>x=5`
`->` B.
\(\Rightarrow x^2\left(x-5\right)+\left(x-5\right)=0\)
\(\Rightarrow\left(x-5\right)\left(x^2+1\right)=0\)
\(\Rightarrow x=5\)
=> Chọn B