a: Ta có: \(\left(x-1\right)^2-25=0\)
\(\Leftrightarrow\left(x+4\right)\left(x-6\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-4\\x=6\end{matrix}\right.\)
b: Ta có: \(\left(2x-5\right)^2-\left(x-2\right)\left(4x+1\right)=1\)
\(\Leftrightarrow4x^2-20x+25-4x^2-x+8x+2=1\)
\(\Leftrightarrow-13x=-26\)
hay x=2
a) \(\Rightarrow\left(x-1\right)^2=25\)
\(\Rightarrow\left[{}\begin{matrix}x-1=5\\x-1=-5\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=6\\x=-4\end{matrix}\right.\)
b) \(\Rightarrow4x^2-20x+25-4x^2+7x+2=1\)
\(\Rightarrow-13x=-26\Rightarrow x=2\)
c) \(\Rightarrow\left(3x-2\right)\left(x-5\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{2}{3}\\x=5\end{matrix}\right.\)
d) \(\Rightarrow x^2-4+x-x^2=2\)
\(\Rightarrow x=6\)
