\(1\\ \left(4x+3y\right)^2=16x^2+24xy+9y^2\\ \left(5x-y\right)^2=25x^2-10xy+y^2\\ 25a^2-9=\left(5a-3\right)\left(5a+3\right)\\ a^2-225=\left(a-15\right)\left(a+15\right)\\ 2,\\ 1,=2y\left(3x+5+8z\right)\\ 2,=\left(x+3\right)\left(y-4\right)\\ 3,=x\left(x-y\right)-y\left(x-y\right)=\left(x-y\right)\left(x-y\right)=\left(x-y\right)^2\)
Bài 1:
1) \(\left(4x+3y\right)^2=16x^2+24xy+9y^2\)
2) \(\left(5x-y\right)^2=25x^2-10xy+y^2\)
3) \(=\left(5a-3\right)\left(5a+3\right)\)
4) \(=\left(a-15\right)\left(a+15\right)\)
Bài 2:
1) \(=2y\left(3x+5+8z\right)\)
2) \(=\left(x+3\right)\left(y-4\right)\)
3) \(=x\left(x-y\right)-y\left(x-y\right)=\left(x-y\right)\left(x-y\right)=\left(x-y\right)^2\)
