đặt a=5k+3,b=5h+4
ab=(5k+3)(5h+4)=25kh+20k+15h+12 chia cho 5 dư 2
Đặt \(a=5k+3,b=5n+4\left(k,n\in N\right)\)
\(\Rightarrow ab=\left(5k+3\right)\left(5n+4\right)=25k^2+35k+12=5\left(5k^2+7k+2\right)+2\)chia 5 dư 2
\(a=5k+3\)
\(b=5c+4\)
\(ab=\left(5k+3\right)\left(5c+4\right)\)
\(=5kc+20k+15c+12\)
\(=5\left(kc+4k+3c+2\right)+2\) chia 5 dư 2(đpcm)