a)\(\left(4x-10\right)\left(24+5x\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}4x-10=0\\24+5x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{2}\\x=-\dfrac{24}{5}\end{matrix}\right.\)
b)\(\left(3,5-7x\right)\left(0,1x+2,3\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}3,5-7x=0\\0,1x+2,3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0,5\\x=-23\end{matrix}\right.\)
a/ \(\text{➝}\text{ }\left(4x-10\right)\left(24+5x\right)=0\)
⇔\(\text{➝}\text{ }4x-10=0\text{⇔}4x=-10\text{⇔}x=-\dfrac{5}{2}\)
\(\text{➝}\text{ }24+5x=0\text{⇔}5x=-24\text{⇔}x=-\dfrac{24}{5}\)
Vậy: Phương trình có nghiệm \(S=\left\{-\dfrac{5}{2};-\dfrac{24}{5}\right\}\)
b/ \(\left(3,5-7x\right)\left(0,1x+2,3\right)=0\)
⇔\(\text{➝}3,5-7x=0\text{⇔}-7x=-3,5\text{⇔}x=\dfrac{1}{2}\)
\(\text{➝}0,1x+2,3=0\text{⇔}0,1x=-2,3\text{⇔}x=-23\)
Vậy: Phương trình có nghiệm \(S=\left\{-23;\dfrac{1}{2}\right\}\)
