Question

xy \3x-2y\-2xy²                

\x² +4x+4\\x+2\

2\x-1\trên x²

trừ x trên \x-1\

Answer 1

+ \(xy\left(3x-2y\right)-2xy^2\)

\(=xy\left(3x-2y-2y\right)\)

\(=3x^2y\)

+ \(\left(x^2+4x+4\right)\left(x+2\right)\)

\(=\left(x+2\right)^2\left(x+2\right)\)

\(=\left(x+2\right)^3\)

+ \(\dfrac{2\left(x-1\right)}{x^2}-\dfrac{x}{x-1}\)

\(=\dfrac{2\left(x-1\right)^2-x^3}{x^2\left(x-1\right)}\)

\(=\dfrac{2\left(x^2-2x+1\right)-x^3}{x^2\left(x-1\right)}\)

\(=\dfrac{2x^2-4x+2-x^3}{x^2\left(x-1\right)}\)

\(=\dfrac{-x^3+2x^2-4x+1}{x^2\left(x-1\right)}\)