\(\left(x+2\right)^2=64\)
\(\Rightarrow\left[{}\begin{matrix}x+2=8\\x+2=-8\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x+6\\x=-10\end{matrix}\right.\)
Lời giải:
$(x+2)^2=64=8^2=(-8)^2$
$\Rightarrow x+2=8$ hoặc $x+2=-8$
$\Rightarrow x=6$ hoặc $x=-10$
(x+2)\(^2\)=64
⇒(x+2)\(^2\)=8\(^2\)
⇒\(\left[{}\begin{matrix}x+2=-8\\x+2=8\end{matrix}\right.\) ⇒\(\left[{}\begin{matrix}x=-10\\x=6\end{matrix}\right.\)