Question

x²-3xy²-3x²y-y²

Answer 1

-(x²+3xy²+3x²y+y²)

=-(x+y)³

Answer 2

\(x^2-3yx^2-3x^2y-y^2\)

\(\left(1-3y\right)x^2-3y^2x-y^2\)

\(\left(x+y\right)\left(-3xy+x-y\right)\)

Answer 3

= (x-y)(x+y) -3xy(x+y)
= (x-y)(x+y-3xy)

 

 

Answer 4

=(x-y)(x+y) -3xy (x+y)
=(x+y)(x-y-3xy)

Answer 5

\(x^2-3xy^2-3x^2y-y^2\)

\(=\left(x^2-y^2\right)-\left(3xy^2+3x^2y\right)\)

\(=\left(x-y\right)\left(x+y\right)-3xy\left(y+x\right)\)

\(=\left(x-y\right)\left(x+y\right)-3xy\left(x+y\right)\)

\(=\left(x+y\right)\left(x-y-3xy\right)\)

Answer 6

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