\(x:\dfrac{1}{7}=\dfrac{1}{4}\\ \Rightarrow x=\dfrac{1}{4}.\dfrac{1}{7}\\ \Rightarrow x=\dfrac{1.1}{4.7}\\ \Rightarrow x=\dfrac{1}{28}\)
x:17=14⇒x=14.17⇒x=1.14.7x=128
\(x:\dfrac{1}{7}=14\)
<=> \(\dfrac{1}{7x}=14\)
ĐKXĐ: x\(\ne\)0
<=> 1 = 14 . 7x
<=> 98x =1
<=> x = \(\dfrac{1}{98}\)
\(x:\dfrac{1}{7}=14\)
\(x=4.\dfrac{1}{7}\)
\(\Rightarrow x=....\)
Ta có: \(x:\dfrac{1}{7}=14\)
\(\Leftrightarrow x=14\cdot\dfrac{1}{7}\)
hay x=2