\(\left(x-7\right).3=27\)
\(< =>x-7=27:3\)
\(< =>x-7=9\)
\(< =>x=9+7\)
\(< =>x=16\)
Vậy ........
\((x-7).3=27\)
\(x-7=27:3\)
\(x-7=9\)
\(x=9+7\)
\(x=16\)
Vậy \(x=16\)
\(\left(x-7\right)^3=27\)
\(\left(x-7\right)^3=3^3\)
\(x-7=3\)
\(x=3+7\)
\(x=10\)