\(x-\dfrac{3}{4}=\dfrac{1}{8}\\ x=\dfrac{1}{8}+\dfrac{3}{4}=\dfrac{7}{8}\)
x - \(\dfrac{3}{4}\)=\(\dfrac{1}{8}\)=>x=\(\dfrac{7}{8}\)
\(x-\dfrac{3}{4}=\dfrac{5}{12}\text{×}\dfrac{3}{10}\\ =>x-\dfrac{3}{4}=\dfrac{1}{8}\\ =>x=\dfrac{1}{8}+\dfrac{3}{4}=\dfrac{1}{8}+\dfrac{6}{8}=\dfrac{7}{8}\)