`(x-3)^2=196`
`(x-3)^2 = (14)^2`
`=> x-3=14`
`x=14+3`
`x=17`
`=> x-3=-14`
`x=-14+3`
`x=-11`
Vậy `x={17;-11}`
\(\left(x-3\right)^2=196\)
\(\Rightarrow\left(x-3\right)^2=\left(\pm14\right)^2\)
\(\Rightarrow\left[{}\begin{matrix}x-3=14\\x-3=-14\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=17\\x=-11\end{matrix}\right.\)
\(\left(x-3\right)^2=14^2\Leftrightarrow x-3=14\Leftrightarrow x=17\)
\(\left(x-3\right)^2=\left(-14\right)^2\Leftrightarrow x-3=-14\Leftrightarrow x=-11\)
(x - 3)^2 = 196
(x - 3)2 = \(\pm\)142
=> x - 3 = \(\pm\) 14
TH1: x - 3 = 14
x = 14 + 3
x = 17
TH2: x - 3 = -14
x = -14 + 3
x = -11
(x - 3)^2= 196
(x - 3)^2= (14)^2
=> TH1: x - 3= 14
x= 14 + 3
x= 17
TH2: x- 3= -14
x= -14 + 3
x= -11
Vậy x thuộc { 17, -11 }