\(\left|x-3\right|=\left|2x-3\right|\)
\(\Rightarrow\left[{}\begin{matrix}x-3=2x-3\\x-3=-\left(2x-3\right)\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}3x=0\\3x=6\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x=2\end{matrix}\right.\)
TH1: x ≥ 3, ta có:
x - 3 = 2x - 3
2x - x = -3 + 3
x = 0 (loại)
3 - x = 2x - 3
2x + x = 3 + 3
3x = 6
x = 6 : 3
x = 2 (nhận)
3 - x = 3 - 2x
-x + 2x = 3 - 3
x = 0 (nhận)
Vậy x = 0; x = 2