Question

Tính

\(\left(4x^4-14x^3-21x-9\right):\left(2x^2-3\right)\)

\(\left(6x^3-2x^2-9x+3\right):\left(3x-1\right)\)

Answer 1

Sửa đề: \(\left(4x^4+14x^3-21x-9\right):\left(2x^2-3\right)\)

\(=\left(4x^4+14x^3+6x^2-6x^2-21x-9\right):\left(2x^2-3\right)\)

\(=\left[\left(4x^4-6x^2\right)+\left(14x^3-21x\right)+\left(6x^2-9\right)\right]:\left(2x^2-3\right)\)

\(=\left[2x^2.\left(2x^2-3\right)+7x.\left(2x^2-3\right)+3.\left(2x^2-3\right)\right]:\left(2x^2-3\right)\)

\(=\left(2x^2+7x+3\right).\left(2x^2-3\right):\left(2x^2-3\right)\)

\(=2x^2+7x+3\)

___________________

\(\left(6x^3-2x^2-9x+3\right):\left(3x-1\right)\)

\(=\left[\left(6x^3-2x^2\right)-\left(9x-3\right)\right]:\left(3x-1\right)\)

\(=\left[2x^2.\left(3x-1\right)-3.\left(3x-1\right)\right]:\left(3x-1\right)\)

\(=\left(2x^2-3\right).\left(3x-1\right):\left(3x-1\right)\)

\(=2x^2-3\)

`#NqHahh`

Answer 2

Answer 3

Answer 4

Answer 5

@Võ Ngọc Phương Sai rồi nhé!

Answer 6

Xin lỗi nha!Do không nhớ để bút xóa trắng ở đâu nên dùng tạm màu trắng á:<

 

Answer 7

Trần Nguyễn Phương Thảo

??? Bằng 0 luôn???

Answer 8

Lỗi 1 tí nhé!Sửa phần kết luận giúp mik nha! 

Answer 9

@Nguyễn Minh Dương

Answer 10

Lộn á!

Answer 11

Phương lmf cũng đúng do khác sách -_-

Answer 12

Sửa đề: (4𝑥4+14𝑥3−21𝑥−9):(2𝑥2−3)(4x4+14x3−21x−9):(2x2−3)

=(4𝑥4+14𝑥3+6𝑥2−6𝑥2−21𝑥−9):(2𝑥2−3)=(4x4+14x3+6x2−6x2−21x−9):(2x2−3)

=[(4𝑥4−6𝑥2)+(14𝑥3−21𝑥)+(6𝑥2−9)]:(2𝑥2−3)=[(4x4−6x2)+(14x3−21x)+(6x2−9)]:(2x2−3)

=[2𝑥2.(2𝑥2−3)+7𝑥.(2𝑥2−3)+3.(2𝑥2−3)]:(2𝑥2−3)=[2x2.(2x2−3)+7x.(2x2−3)+3.(2x2−3)]:(2x2−3)

=(2𝑥2+7𝑥+3).(2𝑥2−3):(2𝑥2−3)=(2x2+7x+3).(2x2−3):(2x2−3)

=2𝑥2+7𝑥+3=2x2+7x+3

___________________

(6𝑥3−2𝑥2−9𝑥+3):(3𝑥−1)(6x3−2x2−9x+3):(3x−1)

=[(6𝑥3−2𝑥2)−(9𝑥−3)]:(3𝑥−1)=[(6x3−2x2)−(9x−3)]:(3x−1)

=[2𝑥2.(3𝑥−1)−3.(3𝑥−1)]:(3𝑥−1)=[2x2.(3x−1)−3.(3x−1)]:(3x−1)

=(2𝑥2−3).(3𝑥−1):(3𝑥−1)=(2x2−3).(3x−1):(3x−1)

=2𝑥2−3=2x2−3