\(\dfrac{-5}{7}\cdot\dfrac{3}{13}-\dfrac{5}{7}\cdot\dfrac{10}{13}+1\dfrac{5}{7}=\dfrac{5}{7}\cdot\dfrac{-3}{13}-\dfrac{5}{7}\cdot\dfrac{10}{13}+\dfrac{12}{7}\cdot1=\dfrac{5}{7}\cdot\left(\dfrac{-3}{13}-\dfrac{10}{13}\right)+\dfrac{12}{7}=\dfrac{5}{7}-1+\dfrac{12}{7}=-\dfrac{5}{7}+\dfrac{12}{7}=\dfrac{7}{7}=1\)
=-5/7(3/13+10/13)+12/7
=-5/7+12/7=1
\(=\dfrac{5}{7}\cdot\left(-\dfrac{3}{13}+\dfrac{10}{13}+1\right)=\dfrac{5}{7}\cdot8=\dfrac{40}{7}\)