Áp dụng t/c dtsbn ta có:
\(\dfrac{x}{5}=\dfrac{y}{3}=\dfrac{z}{6}=\dfrac{x-y}{5-3}=\dfrac{4}{2}=2\)
\(\dfrac{x}{5}=2\Rightarrow x=10\\ \dfrac{y}{3}=2\Rightarrow y=6\\ \dfrac{z}{6}=2\Rightarrow z=12\)
Áp dụng t/c dtsbn:
\(\dfrac{x}{5}=\dfrac{y}{3}=\dfrac{z}{6}=\dfrac{x-y}{5-3}=2\)
\(\Rightarrow\left\{{}\begin{matrix}x=10\\y=6\\z=12\end{matrix}\right.\)
\(\dfrac{x-y}{5-3}=\dfrac{4}{2}=2\\ \)
=> \(\dfrac{x}{5}=5\cdot2=10\\ \)
=> \(\dfrac{x}{3}=3\cdot2=6\)
=>\(\dfrac{z}{6}=6\cdot2=12\)
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