Question

Tìm x:

(2x-3)^2 = (x-1)^2

Answer 1

`(2x-3)^2=(x-1)^2`

`=> (2x-3)^2 - (x-1)^2=0`

`=> (2x-3-x+1)(2x-3+x-1)=0`

`=> (x -2)(3x-4)=0`

`=> [(x-2=0),(3x-4=0):}`

`=> [(x=2),(x=4/3):}`

Vậy: `S={2;4/3}`

Answer 2

 

\(\left(2x-3\right)^2-\left(x-1\right)^2=0\)

 (2x-3-x+1)(2x-3+x-1) =0

(x-4)(3x-4) = 0

Ta có 2 TH

+) TH1:

x-4=0

x=4

+) TH2:

3x-4=0

x=\(\dfrac{4}{3}\)

Vậy x=4; x=\(\dfrac{4}{3}\)