\(\dfrac{2}{3}\div x+\dfrac{2}{3}=\dfrac{1}{6}\)
\(\dfrac{2}{3}\div x=\dfrac{1}{6}-\dfrac{2}{3}\)
\(\dfrac{2}{3}\div x=-\dfrac{1}{2}\)
\(x=\dfrac{2}{3}\div\left(-\dfrac{1}{2}\right)\)
\(x=-\dfrac{4}{3}\)
\(\dfrac{2}{3}:x+\dfrac{2}{3}=\dfrac{1}{6}\)
\(\Leftrightarrow\dfrac{2}{3}:x=\dfrac{1}{6}-\dfrac{2}{3}\)
\(\Leftrightarrow\dfrac{2}{3}:x=-\dfrac{1}{2}\)
\(\Leftrightarrow x=\dfrac{2}{3}:-\dfrac{1}{2}\)
\(\Leftrightarrow x=-\dfrac{4}{3}\)
2/3 : x + 2/3 = 1/6
2/3 : x = 1/6 - 2/3
2/3 : x = -1/2
x = 2/3 : (-1)/2
x = -4/3
vậy x =....