`2 . ( 1 / 2 x - 1 / 3 ) + 3 / 2 = 1 / 4`
`2 . ( 1 / 2 x - 1 / 3 ) = 1 / 4 - 3 / 2`
`2 . ( 1 / 2 x - 1 / 3 ) = [-5] / 4`
`1 / 2 x - 1 / 3 = [-5] / 4 : 2`
`1 / 2 x - 1 / 3 = [-5] / 8`
`1 / 2 x = [-5] / 8 + 1 / 3`
`1 / 2 x = [-7] / 24`
`x =[-7] / 24 : 1 / 2`
`x = [-7] / 12`
\(\left(\dfrac{1}{2}x-\dfrac{1}{3}\right)+\dfrac{3}{2}=\dfrac{1}{4}\\ \dfrac{1}{2}x-\dfrac{1}{3}=\dfrac{1}{4}-\dfrac{3}{2}\\ \dfrac{1}{2}x-\dfrac{1}{3}=\dfrac{-5}{4}\\ \dfrac{1}{2}x=\dfrac{-5}{4}+\dfrac{1}{3}\\ \dfrac{1}{2}x=\dfrac{-11}{12}\\ x=\dfrac{-11}{12}:\dfrac{1}{2}\\ x=\dfrac{-11}{12}.\dfrac{2}{1}\\ x=\dfrac{-11}{6}\)
\(#tai\)
\(2\left(\dfrac{1}{2}x-\dfrac{1}{3}\right)+\dfrac{3}{2}=\dfrac{1}{4}\\ 2\left(\dfrac{1}{2}x-\dfrac{1}{3}\right)=\dfrac{1}{4}-\dfrac{3}{2}\\ 2\left(\dfrac{1}{2}x-\dfrac{1}{3}\right)=-\dfrac{5}{4}\\ \dfrac{1}{2}x-\dfrac{1}{3}=\left(-\dfrac{5}{4}\right):2\\ \dfrac{1}{2}x-\dfrac{1}{3}=-\dfrac{5}{8}\\ \dfrac{1}{2}x=\left(-\dfrac{5}{8}\right)+\dfrac{1}{3}\\ \dfrac{1}{2}x=-\dfrac{7}{24}\\ x=\left(-\dfrac{7}{24}\right):\dfrac{1}{2}\\ x=-\dfrac{7}{12}\)
Vậy `x=-7/12`
2.(1/2x-1/3)+3/2=1/4
2.(1/2x-1/3)=1/4-3/2
2.(1/2x-1/3)=-5/4
1/2x-1/3=-5/4÷2
1/2x-1/3=-5/8
1/2x=-5/8+1/3
1/2x=-7/24
x=-7/24÷1/2
x-7/12
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