Question

tìm x:

Answer 1

\(3\dfrac{1}{3}x+16\dfrac{3}{4}=-13,25\\ =>\dfrac{10}{3}x+\dfrac{67}{4}=-\dfrac{53}{4}\\ =>\dfrac{10}{3}x=-\dfrac{53}{4}-\dfrac{67}{4}\\ =>\dfrac{10}{3}x=-30\\ =>x=\left(-30\right):\dfrac{10}{3}\\ =>x=-9\)

Answer 2

\(3\dfrac{1}{3}x+16\dfrac{3}{4}=-13,25\)

\(\Leftrightarrow\dfrac{10}{3}x+\dfrac{67}{4}=-\dfrac{53}{4}\)

\(\Leftrightarrow\dfrac{10}{3}x=-\dfrac{53}{4}-\dfrac{67}{4}\)

\(\Leftrightarrow\dfrac{10}{3}x=-30\)

\(\Leftrightarrow x=-30:\dfrac{10}{3}\)

\(\Leftrightarrow x=-9\)

Answer 3

`3 1/3 x + 16 3/4=-13,25`

`=> 10/3x + 67/4=-13,25`

`=> 10/3x=-13,25-67/4`

`=> 10/3x=-30`

`=>x=-30 : 10/3`

`=>x=-30 xx 3/10`

`=>x=-9`

Answer 4

\(3\dfrac{1}{3}x+16\dfrac{3}{4}=-13,25\)

\(\dfrac{10}{3}x+\dfrac{67}{4}=\dfrac{-53}{4}\)

\(\dfrac{10}{3}x=\dfrac{-53}{4}-\dfrac{67}{4}\)

\(\dfrac{10}{3}x=-30\)

\(x=-30:\dfrac{3}{10}\)

\(x=-9\)

Answer 5

\(3\dfrac{1}{3}x+16\dfrac{3}{4}=-13,25\)

  \(\dfrac{10}{3}x+\dfrac{67}{4}=\dfrac{-53}{4}\)

            \(\dfrac{10}{3}x=\dfrac{-53}{4}-\dfrac{67}{4}\)

            \(\dfrac{10}{3}x=\dfrac{-120}{4}=-30\)

                  \(x=-30:\dfrac{10}{3}\)

                  \(x=-30.\dfrac{3}{10}=-9\)