=>3x-2x^2-3+2x+2x^2+6x-x-3=14
=>10x-6=14
=>x=2
\(\left(x-1\right)\left(3-2x\right)+\left(2x-1\right)\left(x+3\right)=14\)
\(\Leftrightarrow3x-2x^2-3+2x+2x^2+6x-x-3=14\)
\(\Leftrightarrow\left(-2x^2+2x^2\right)+\left(3x+2x+6x-x\right)-\left(3+3\right)=14\)
\(\Leftrightarrow10x-6=14\)
\(\Leftrightarrow10x=14+6\)
\(\Leftrightarrow10x=20\)
\(\Leftrightarrow x=20:10\)
\(\Leftrightarrow x=2\)
Vậy: \(x=2\)