(x - 1/2) . (5 . x - 1/3) = 0`
`=> [(x - 1/2 = 0),(5x - 1/3 = 0):}`
`=> [(x = 1/2),(5x = 1/3):}`
`=> [(x = 1/2),(x = 1/15):}`
Vậy: `x=1/2;x=1/15`
\(\left(x-\dfrac{1}{2}\right)\left(5x-\dfrac{1}{3}\right)=0\)
=>\(\left[{}\begin{matrix}x-\dfrac{1}{2}=0\\5x-\dfrac{1}{3}=0\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}x=\dfrac{1}{2}\\5x=\dfrac{1}{3}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=\dfrac{1}{3}:5=\dfrac{1}{15}\end{matrix}\right.\)
\(\left(x-\dfrac{1}{2}\right).\left(5x-\dfrac{1}{3}\right)=0\)
\(x-\dfrac{1}{2}=0\) hoặc \(5x-\dfrac{1}{3}=0\)
\(x=0+\dfrac{1}{2}\) hoặc \(5x=0+\dfrac{1}{3}\)
\(x=\dfrac{1}{2}\) hoặc \(5x=\dfrac{1}{3}\)
\(x=\dfrac{1}{2}\) hoặc \(x=\dfrac{1}{3}:5\)
\(x=\dfrac{1}{2}\) hoặc \(x=\dfrac{1}{15}\)
Vậy .....