Question

Tìm x biết

x(x-2022)-(2022-x)=0

x²-8x+15=0

MIK ĐANG CẦN GẤP

Answer 1

a: =>(x-2022)(x+1)=0

=>x=2022 hoặc x=-1

b: =>(x-3)(x-5)=0

=>x=3 hoặc x=5

Answer 2

`x(x-2022)-(2022-x)=0`

`<=> x^2 - 2022x - 2022 +x =0`

`<=> x^2 +x - 2022x -2022 =0`

`<=> x(x+1)-2022(x+1) =0`

`<=> (x-2022)(x+1)=0`

`<=>`\(\left[{}\begin{matrix}x-2022=0\\x+1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2022\\x=-1\end{matrix}\right.\)

Vậy `S={2022;-1}`

`x^2 -8x+15 =0`

`<=> x^2 -3x -5x +15=0`

`<=> x(x-3) - 5(x-3) =0`

`<=>(x-3)(x-5)=0`

`<=>`\(\left[{}\begin{matrix}x=3\\x=5\end{matrix}\right.\)

Vậy `S={3;5}`