Question

Tìm x, biết:

\(a.\dfrac{-2}{3}\cdot x+\dfrac{1}{5}=\dfrac{3}{10}\)

\(b.\dfrac{2}{3}x-\dfrac{1}{2}=\dfrac{1}{10}\)

\(c.\dfrac{3}{2}x-\dfrac{11}{5}=\dfrac{7}{8}\cdot\dfrac{64}{48}\)

Answer 1

`a, -2/3 x = 1/10`

`=> x = 1/10 : -2/3 = -3/20`

`b, 2/3 x - 1/2 = 1/10`

`=> 2/3 x = 1/10 + 1/2`

`=> 2/3 x = 3/5`

`=> x = 3/5 : 2/3`

`=> x = 9/10`

`c, 3/2x - 11/5 = 7/6`

`=> 3/2 x = 101/30`

`=> x = 101/30 : 3/2`

`=> x=  101/45.`

Answer 2

`(-2)/3 . x + 1/5 = 3/10`

`(-2)/3 . x = 3/10 - 1/5`

`(-2)/3 . x = 1/10`

`x = 1/10 : (-2)/3`

`x = 1/10 . (-3)/2`

`x = (-3)/20`

 

`2/3x - 1/2 = 1/10`

`2/3x = 1/10 + 1/2`

`2/3x = 3/5`

`x = 3/5 : 2/3`

`x = 9/10`

 

`3/2x - 11/5 = 7/8 . 64/48`

`3/2x - 11/5 = 7/6`

`3/2x = 7/6 + 11/5`

`3/2x = 101/30`

`x = 101/30 : 3/2`

`x = 101/45`

Answer 3

`(-2)/3 . x + 1/5 = 3/10`

`(-2)/3 . x = 3/10 - 1/5`

`(-2)/3 . x = 1/10`

`x = 1/10 : (-2)/3`

`x = 1/10 . (-3)/2`

`x = (-3)/20`

________________________________

`2/3x - 1/2 = 1/10`

`2/3x = 1/10 + 1/2`

`2/3x = 3/5`

`x = 3/5 : 2/3`

`x = 3/5 . 3/2`

`x = 9/10`

________________________

`3/2x - 11/5 = 7/8 . 64/48`

`3/2x - 11/5 = 7/6`

`3/2x = 7/6 + 11/5`

`3/2x = 101/30`

`x = 101/30 : 3/2`

`x = 101/30 . 2/3`

`x = 101/45`