Question

tìm x biết (x+3)^2+(x-2)^2=2x^2

giúp tui

Answer 1

\(\left(x+3\right)^2+\left(x-2\right)^2=2x^2\\ \Leftrightarrow x^2+6x+9+x^2-4x+4=2x^2\\ \Leftrightarrow2x=-13\Leftrightarrow x=-\dfrac{13}{2}\)

Answer 2

<=> x²+6x+9+x²+4x+4-2x² =0

<=>10x+13=0

<=> x= -13/10

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Answer 3

`(x+3)^2 +(x-2)^2=2x^2`

`<=>x^2+6x+9 +x^2-4x+4-2x^2=0`

`<=> 2x +13=0`

`<=>2x=-13`

`<=>x=(-13)/2`

vậy `x=(-13)/2`