Question

Tìm x ,biết

\(2x^2-2x=\left(x-1\right)^2\)

Answer 1

\(2x^2-2x=\left(x-1\right)^2\)

\(\Rightarrow2x\left(x-1\right)-\left(x-1\right)^2=0\)

\(\Rightarrow\left(x-1\right)\left(2x-x+1\right)=0\Rightarrow\left(x-1\right)\left(x+1\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x=1\\x=-1\end{matrix}\right.\)

Answer 2

\(2x^2-2x=\left(x-1\right)^2\)

\(2x\left(x-1\right)=\left(x-1\right)^2\)

\(2x\left(x-1\right)-\left(x-1\right)^2=0\)

\(\left(x-1\right)\left(2x-x+1\right)=0\)

\(\left(x-1\right)\left(x+1\right)=0\)

⇔\(\left[{}\begin{matrix}x-1=0\\x+1=0\end{matrix}\right.\)

⇔\(\left[{}\begin{matrix}x=1\\x=-1\end{matrix}\right.\)