ta có
\(90 = 5.3^2.2\)
\(180 = 5.3^2.2^2\)
\(315 = 5.3^2.7\)
\(=>ƯCLN (90,180,315) = 5.3^2 = 45\)
\(Ư(45)={1,45,3,15,5,9}\)
\(90=2.3^2.5\)
\(180=2^2.3^2.5\)
\(315=3^2.5.7\)
\(ƯCLN\left(90;180;315\right)=3^2.5=45\)
\(ƯC\left(45\right)=\left\{1;3;5;9;15;45\right\}\)
`90 = 2 . 3^2 . 5`
`180 = 2^2 . 3^2 . 5`
`315 = 3^2 . 5 .7`
`=> ƯCLN (90,180,315) = 3^2 . 5 = 45`
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`90 = { 1,2,3,5,6,9,10,15,30,45}`
`180 = { 1,2,3,4,5,6,9,10,12,15,18,20,30,36,45}`
`315 = { 1,3,5,7,9,15,21,35,45...}`
`=> ƯC ( 90,180,315) = { 1,3,5,9,15,45}`
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`#BaoL i nh`