Bài toán thỏa mãn khi:
\(\left\{{}\begin{matrix}2-2m>0\\2-2m=m^2-1\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}m< 1\\m^2+2m-3=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}m< 1\\\left\{{}\begin{matrix}m=1\\m=-3\end{matrix}\right.\end{matrix}\right.\) \(\Rightarrow m=-3\)