\(\text{Ta có:}\dfrac{x}{8}=\dfrac{2}{x}\)
\(\Rightarrow\dfrac{x}{8}.8x=\dfrac{2}{x}.8x\)
\(\Rightarrow x^2=16\)
\(\Rightarrow\left[{}\begin{matrix}x^2=\left(-4\right)^2\\x^2=4^2\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-4^{ }\\x^{ }=4^{ }\end{matrix}\right.\)
\(\text{Vậy }x\in\left\{-4;4\right\}\)
\(\dfrac{2}{x}=\dfrac{x}{8}\)
nên \(x^2=16\)
hay \(x\in\left\{4;-4\right\}\)
Ta có 2/x=x/8 ->x.x=2.8->x mũ 2=16 <-> x=4 hoặc x=-4