Để M là số nguyên thì xy+x+1⋮ xy+x+2
=>xy+x+2-1⋮ xy+x+2
=>-1⋮xy+x+2
=>xy+x+2=1 hoặc xy+x+2=-1
Th1: xy+x+2=1
=>x(y+1)=-1
=>(x;y+1)∈{(1;-1);(-1;1)}
=>(x;y)∈{(1;-2);(-1;0)}
TH2: xy+x+2=-1
=>xy+x=-1-2=-3
=>x(y+1)=-3
=>(x;y+1)∈{(1;-3);(-3;1);(-1;3);(3;-1)}
=>(x;y)∈{(1;-4);(-3;0);(-1;2);(3;-2)}