\(\sqrt{\frac{\left(\sqrt{3}-1\right)\left(\sqrt{3}+1\right)-\sqrt{3}}{2}}\)
\(=\sqrt{\frac{3-1-\sqrt{3}}{2}}=\sqrt{\frac{2-\sqrt{3}}{2}}\)
\(=\frac{\sqrt{2}\sqrt{2-\sqrt{3}}}{2}=\frac{\sqrt{4-2\sqrt{3}}}{2}\)
\(=\frac{\sqrt{3-2\sqrt{3}+1}}{2}=\frac{\sqrt{\left(\sqrt{3}-1\right)^2}}{2}=\frac{\sqrt{3}-1}{2}\)
Chị mk đang làm giup mk chờ xíu nha .