Question

\(\sqrt{12}\)-\(\sqrt{27}\)+\(\sqrt{48}\)

Answer 1

\(\sqrt{12}-\sqrt{27}+\sqrt{48}\)

\(=2\sqrt{3}-3\sqrt{3}+4\sqrt{3}\)

\(=6\sqrt{3}-3\sqrt{3}=3\sqrt{3}\)

Answer 2

Lời giải:

$\sqrt{12}-\sqrt{27}+\sqrt{48}=2\sqrt{3}-3\sqrt{3}+4\sqrt{3}$

$=(2-3+4)\sqrt{3}=3\sqrt{3}$

Answer 3

\(\sqrt{12}-\sqrt{27}+\sqrt{48}=2\sqrt{3}-3\sqrt{3}+4\sqrt{3}=3\sqrt{3}\)

Answer 4

\[
2\sqrt{3} - 3\sqrt{3} + 4\sqrt{3}
\]
\[
(2 - 3 + 4)\sqrt{3} = 3\sqrt{3}
\]

=>  \(3\sqrt{3}\).