Question

\(\sqrt{12}+4\sqrt{27}-3\sqrt{48}\)

Answer 1

\(\sqrt{12}+4\sqrt{27}-3\sqrt{48}\)

\(=\sqrt{2^2\cdot3}+4\sqrt{3^2\cdot3}-3\sqrt{4^2\cdot3}\)

\(=2\sqrt{3}+4\cdot3\sqrt{3}-3\cdot4\sqrt{3}\)

\(=2\sqrt{3}+12\sqrt{3}-12\sqrt{3}\)

\(=2\sqrt{3}\)

Answer 2

\(=2\sqrt{3}+4\cdot3\sqrt{3}-3\cdot4\sqrt{3}\)

\(=2\sqrt{3}+12\sqrt{3}-12\sqrt{3}\)

=2căn 3

Answer 3

\(\sqrt{12}+4\sqrt{27}-3\sqrt{48}\\ =\sqrt{2^2.3}+4\sqrt{3.3^2}-3.\sqrt{3.4^2}\\ =2\sqrt{3}+4.3.\sqrt{3}-3.4\sqrt{3}\\ =2\sqrt{3}+12\sqrt{3}-12\sqrt{3}=2\sqrt{3}\)