16 = 9 + 7 = 9 + √49
9 + 4√5 = 9 + √80
Do 49 < 80 nên √49 < √80
⇒ 9 + √49 < 9 + √80
Vậy 16 < 9 + 4√5
Ta có:
\(16=9+5=9+\sqrt{25}\)
\(9+4\sqrt{5}=9+\sqrt{4^2\cdot5}=9+\sqrt{20}\)
Mà: \(20< 25\)
\(\Rightarrow\sqrt{20}< \sqrt{25}\)
\(\Rightarrow9+\sqrt{20}< 9+\sqrt{25}\)
\(\Rightarrow9+4\sqrt{5}< 16\)
Giả sử \(16< 9+4\sqrt[]{5}\)
\(\Leftrightarrow7< 4\sqrt[]{5}\)
\(\Leftrightarrow7^2< \left(4\sqrt[]{5}\right)^2\)
\(\Leftrightarrow49< 80\left(luôn.đúng\right)\)
Vậy \(16< 9+4\sqrt[]{5}\)