\(\sqrt{3-\sqrt{5}}\\ =\dfrac{\sqrt{2}.\sqrt{3-\sqrt{5}}}{\sqrt{2}}\\ =\dfrac{\sqrt{6-2\sqrt{5}}}{\sqrt{2}}=\dfrac{\sqrt{\left(\sqrt{5}-1\right)^2}}{\sqrt{2}}=\dfrac{\sqrt{5}-1}{\sqrt{2}}=\dfrac{\sqrt{2}\left(\sqrt{5}-1\right)}{2}=\dfrac{\sqrt{10}-\sqrt{2}}{2}\)