Question

Rút gọn

\(\frac{1}{xy}.\sqrt{\frac{x^2y^2}{2}}\)                            \(\frac{3}{a^2-b^2}.\sqrt{\frac{2\left(a+b\right)^2}{9}}\)

\(\left(x-2y\right)\sqrt{\frac{4}{\left(2y-x\right)^2}}\)                    \(\left(x-y\right)\sqrt{\frac{3}{y-x}}\)

Giúp mik zs

Answer 1

\(\frac{1}{xy}\cdot\sqrt{\frac{x^2y^2}{2}}=\frac{1}{xy}\cdot\frac{xy}{\sqrt{2}}=\frac{1}{\sqrt{2}}\)

\(\frac{3}{a^2-b^2}\cdot\sqrt{\frac{2\left(a+b\right)^2}{9}}=\frac{3}{a^2-b^2}\cdot\frac{\sqrt{2}\left(a+b\right)}{3}=\frac{\sqrt{2}}{a-b}\)

\(\left(x-2y\right)\sqrt{\frac{4}{\left(2y-x\right)^2}}=\left(x-2y\right)\cdot\frac{2}{\left(x-2y\right)}=2\)

 

Answer 2

câu 1 chưa có điều kiện x y mà lại không cho giá trị tuyệt đối