Question

Rút gọn:

\(\dfrac{a^2+\left(a-c\right)^2}{b^2+\left(b-c\right)^2}\)

với: c²+2ab-2ac-2bc=0; b\(\ne\)c; a+b\(\ne\)c

Answer 1

Tham khảo:

Cho a≠b≠c, a+b≠c và c2+2ab-2ac-2bc=0 Hãy rút gọn \(B=\frac{a^2+\left(a-c\right)^2}{b^2+\left(b-c\right)^2}\) - Hoc24

Answer 2

\(\dfrac{a^2+\left(a-c\right)^2}{b^2+\left(b-c\right)^2}\)

\(=\dfrac{a^2+a^2-2ac+c^2}{b^2+b^2-2bc+c^2}\)

\(=\dfrac{2a^2-2ac+c^2}{2b^2-2bc+c^2}\)