\(=\dfrac{3\sqrt{3}\left(\sqrt{3}-1\right)}{3\sqrt{15}}=\dfrac{\sqrt{3}-1}{\sqrt{5}}=\dfrac{\sqrt{15}-\sqrt{5}}{5}\)
\(=\dfrac{3\sqrt{3}\left(\sqrt{3}-1\right)}{3\sqrt{15}}=\dfrac{\sqrt{3}-1}{\sqrt{5}}=\dfrac{\sqrt{15}-\sqrt{5}}{5}\)
Rút gọn: \(2\sqrt{40\sqrt{12}}+3\sqrt{5\sqrt{48}}-2\sqrt{\sqrt{75}}-4\sqrt{15\sqrt{27}}\)
rút gọn
\(y=\frac{3\sqrt{8}-2\sqrt[]{12}+\sqrt{20}}{3\sqrt{18}-2\sqrt{27}+\sqrt{15}}\)
Rút gọn biểu thức
A= \(2\sqrt{27}-\sqrt{\left(1-\sqrt{3}\right)^2}+\dfrac{1}{2-\sqrt{3}}\)
Help me
Rút gọn các biểu thức sau a)√27-✓12+✓48-5✓3 b)5✓18-✓5+✓20+✓1 2 C)✓25:✓16=✓36:✓9 D)✓12+✓27-5✓3 E)2✓3-✓75+2✓12
\(\sqrt{27+10\sqrt{2}}-3\sqrt{2}\)
Rút gọn
rút gọn biểu thức :
A= \(\dfrac{\sqrt{4+\sqrt{3}}+\sqrt{4-\sqrt{3}}}{\sqrt{4+\sqrt{13}}}+\sqrt{27-10\sqrt{2}}\).
B= \(\dfrac{\sqrt{2-\sqrt{3}}+\sqrt{4-\sqrt{15}}+\sqrt{10}}{\sqrt{23-3\sqrt{5}}}\).
C= \(\dfrac{\sqrt{2}+\sqrt{3}+\sqrt{6}+\sqrt{8}+4}{\sqrt{2}+\sqrt{3}+\sqrt{4}}\).
rút gọn biểu thức
A=2\(\sqrt{27}\)+5\(\sqrt{12}\)-3\(\sqrt{48}\)
B=\(\sqrt{147}\)+\(\sqrt{75}\)-4\(\sqrt{27}\)
C=3\(\sqrt{2}\)(4-\(\sqrt{2}\))+3(1-2\(\sqrt{2}\))2
D=2\(\sqrt{5}\)-\(\sqrt{125}\)-\(\sqrt{80}\)+\(\sqrt{605}\)
Rút gọn (toán lớp 9)
a,√405+3√27/3√3+√45
b,√6-2√5/√5-1
Rút gọn: \(M=\dfrac{8}{\sqrt{5}-\sqrt{3}}+\dfrac{7}{\sqrt{3}-2}+\dfrac{4}{\sqrt{2}-1}+\dfrac{3\sqrt{5}-\sqrt{15}}{\sqrt{15}}\)