Question

Rút gọn biểu thức 

\(\left|x-2\right|+\dfrac{\sqrt{x^2-4x+4}}{x-2}\) với \(x< 2\)

Answer 1

\(\left|x-2\right|+\dfrac{\sqrt{x^2-4x+4}}{x-2}=\left|x-2\right|+\dfrac{\sqrt{\left(x-2\right)^2}}{x-2}=\left|x-2\right|+\dfrac{\left|x-2\right|}{x-2}=2-x+\dfrac{2-x}{x-2}=2-x-\dfrac{x-2}{x-2}=2-x-1=1-x\)

Answer 2

\(=2-x+\dfrac{\left|x-2\right|}{x-2}=2-x-1=1-x\)